Question

A 25 kg crate is moved through a distance of 4 m by a horizontal force of 60 N. What is the work done by the frictional force in moving the crate if the coefficient of kinetic friction is 0.2?


240 J

-240 J

-196 J

196 J

Answer 1

@SuperflyTyGuy

Answer 2

@Catlover5925

Answer 3

Frictional force = 0.2 x 25 x 9.81 = 49.05 N
work done = 49.05 x 4 =196.2 J


I think it's D.

Answer 4

thats what i put but it got marked wrong!! ughhhh:(((

Answer 5

uhh sorry i cant help you i dont remember any of this

Answer 6

Aargh I keep getting 196!

Answer 7

thats ok thanks anyway

Answer 8

ugh ik its so annoying wtf is wrong w my teacher!! do y'all know this one (sorry for so many questions)
A spring gains an elastic potential energy of 5 J when it is compressed 50 cm from its original length. What is the force constant of the spring?


10 N/m

20 N/m

40 N/m

50 N/m

Answer 9

P.E. = Force x distance
5 = F x 0.5
f = 10 N

Answer 10

thanks!!

Answer 11

do u think it could be -196? @SuperflyTyGuy

Answer 12

I think so

Answer 13

@SuperflyTyGuy thank u!!

Answer 14

You're welcome! :D