FAN AND MEDAL PLEASE HELP Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are inverses. f(x) x+a/b g(x)=cx−d Part 2. Show your work to prove that the inverse of f(x) is g(x). @ganeshie8 @amistre64 @uri
btw its g(x)=cx-d
lets start with how do you define an inverse?
I think it is an opposite
an inverse undoes .... is a good way to look at it, but more mathically: if f and g are inverses then: f(g(x)) = x AND g(f(x)) = x for all x
but it says to insert numbers for them and then explain how they are inverses i just dont understand this lesson at all.
well, we need to determine what values will make them inverses; so lets start by making the compositions and then see where it leads us
okay
is it f = (x+a)/b, or f = x + (a/b)
the first one
then f(g) = (g+a)/b = (cx-d+a)/b is an inverse at best if f(g) = x and g(f) = cf-d = c(x+a)/b - d is an inverse at best if g(f) = x since x=x, when does: (cx-d+a)/b = c(x+a)/b - d
or we might be able to work it simpler one by one c(x+a)/b - d = x and (cx-d+a)/b = x either way we should be able to get some options worked out for us
okay so now we plug in numbers?
we can start plugging numbers sure, like b=1 might be a good start
so now its c(x+a)/1-d=x and (cx-d)/1=x
or work it all out such that (cx-d+a)/b = c(x+a)/b - d cx-d+a = c(x+a) - bd cx-d+a = cx+ca - bd -d+a = ca - bd
so nvm its -d+a=ca-1d?
well, from this, if we let b=1 and c=1 a-d = 1a - 1d is true for any values of a and d
oh okay so is that the answer for part 1 and 2
well, part 1 says to find some abcd values that make f and g inverses. part 2 says to prove that those values work
show that f(g) = x and g(f) = x for c=1, b=1, a=a, d=d
okay
of course pick your favorite a and d values since they seem to be unimportant overall
6
so a=6, and d=?
4
that should work fine :)
so: f = (x+6)/1, g=1x-4 f(g) = (x-4)+6 doesnt equal x so we might have to try this again. might be a typo up there
what do you mean?
Dang it i have to go in like 30 mins
f = (x+a)/b g = cx - d ---------------------- f(g) = (cx-d+a)/b g(f) = c(x+a)/b - d --------------------- inverses are defined as: f(g) = x g(f) = x (cx-d+a)/b = x c(x+a)/b - d = x cx +a -d = bx cx +ca - bd = bx let b=1 cx +a -d = x cx +ca - d = x let c=1 x +a - d = x x +a - d = x a-d = 0 if a=d is where we went wrong
if a=6, then d=6
the process of determining abcd is actually proves they are inverses, but they seem to want you to go about it in a backwards kind of way.
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