I need help with 3 x (1/2)^x an exponential function, can someone go through domain, range, horozontal aysmptote, and graphing
the range is y>1
if x is 0 y=2 the domain is all real numbers.
Domain is all Real x
and the horizontal asymptote is 1
please keep in mind that the graph of y=f(x)=2^x, is: |dw:1418332220519:dw| so in order to get your graph we have to add to y-corrdinates of all point of 2^x, the quantity +1
I don't understand the drawing of the graph
it is a standard graph which you can find on your textbook
do you understand why it pass through y = 1?
for example, I write these limits: \[\lim _{x \rightarrow +\infty} 2^{x}=+\infty\] and \[\lim _{x \rightarrow -\infty}2^{x}=0\] do you agree?
ooops sorry it should pass through y=2
I'm sorry but I have the wrong problem up, it's \[3 \times (1/2)^{x}\]
yep. make x 0 and you get 1 + 1.
the y intercept is at y=3
|dw:1418332657326:dw|
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