Question

(1-sec(-x))/(1-cos(-x))
I have to show work, I got this far:
(1-secx)/(1+cosx)

Answer 1

cos(-x) = cos(x)

Answer 2

Oh!

Answer 3

other than that,

\[\frac{1-\frac{1}{cos}}{1+cos}\]
\[\frac{cos-1}{cos(1+cos)}\]
\[\frac{cos-(cos^2+sin^2)}{cos+(1-sin^2)}\]
\[\frac{cos-cos^2-sin^2}{cos-sin^2+1}\]
not really sure what it is you are trying to accomplish so this might be going off into left field

Answer 4

lol, i got confused and kept the bottom as 1+cos

Answer 5

None of that showed up, but I have to find the most compact answer.

Answer 6

sec = 1/cos, sooo

1 - 1/cos
---------
1 - cos

and shake it out

Answer 7

cos - 1
---------
cos(1-cos)


cos - 1
---------
-cos(cos-1)

-1/cos = -sec

Answer 8

How did you get that?

Answer 9

i posted all the work, not sure whats not being followed

Answer 10

How does 1-1/cos turn into cos-1?

Answer 11

adding fractions

1 - a/b = (b-a)/b

Answer 12

Oh, I get that.

Answer 13

ergo

cos-1 1
----- * -----
cos 1-cos

Answer 14

What does that go to?

Answer 15

factor our a -1, and cancel like factors

Answer 16

And why is (1-cosx) multiplied by cosx?

Answer 17

(cos-1)/cos = -(1-cos)/cos

Answer 18

all this is is fractions

Answer 19

1 - a/b
-------
1-b



(1 - a/b) * 1
-------
1-b


b - a 1
----- * -------
b 1-b

Answer 20

let b = cos, and a=1

Answer 21

I get it now, thank you.

Answer 22

youre welcome