Question

help

Answer 1

hey!! how can it be hard?

Answer 2

just take integral term by term.

Answer 3

show it

Answer 4

hey, this is INTEGRAL, not DERIVATIVE. :)

Answer 5

\((\dfrac{x^3}{4})'= \dfrac{3x^2}{4}\)
but \[\int \dfrac{x^3}{4}= \dfrac{x^4}{4*4}=\dfrac{x^4}{16}\]

Answer 6

ok, redo

Answer 7

yup