Question

write the slope-intercept form of the equation of the line passing through (4, -6) and parallel to the line y= 8x-2

Answer 1

what do we know about parallel lines?

Answer 2

I've kinda forgotten everything to be honest.

Answer 3

ok so parallel lines can't intersect each other. so they both have the same slope. since we know that the line goes through point (4,-6) and the slope must be 8, we can use point-slope form: y - y1 = m(x - x1)

Answer 4

so plug in your info and then convert it into slope-intercept form

Answer 5

You found a pro alex xD

Answer 6

what would i use for y and y1 and x and x1

Answer 7

y and x stay the same. y1 is the y part of the point and x1 is the x part of the point. so y1 = -6 and x1 = 4

Answer 8

and m would be 8 right?

Answer 9

yes

Answer 10

okay thank you so much!

Answer 11

wait you're not done yet tho cuz you have to convert it into slope-intercept form before you submit it

Answer 12

This is such simple math but I love watching you break it down for alex @AriPotta

Answer 13

#Proatwork

Answer 14

so since y1 would be -6 and the equation is y-y1 would it be y-(-6) and then the rest of the equation?

Answer 15

y - (-6) = 8(x - 4)
y + 6 = 8(x - 4)

Answer 16

when you subtract a negative, it turns into addition

Answer 17

but you're not done yet since your answer has to be in slope-intercept form

Answer 18

I'm not sure if I've done the equation right so far. i started with y-(-6)= 8(x-4) then i switched it to y+6= 8x-32 and subtracted 6 from each side and got y=8x - 38

Answer 19

that's exactly right :)

Answer 20

is that all I have to do?

Answer 21

yep.

Answer 22

okay thank you! :)

Answer 23

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