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OpenStudy (hackergod):
I need help and explanation to a problem please. fan and medal
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OpenStudy (hackergod):
2H2S(g)+3O2(g)-->2SO2(g)+2H2O(g)
OpenStudy (hackergod):
If O2 was the excess reagent 8.3 mol of H2S were consumed, and 137.1g of water were collected after the reaction has gone to completion what is the percent yield of the reaction?
OpenStudy (anonymous):
Okay! So first, you would change 137.1 grams to moles. Do you know how to do so?
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