Question

Another question again, is there any way in which I could find all irrational roots of a function?
The function is: (x^3)/(3)-(x^2)/(2)-2x+(1/3)
Thank you!

Answer 1

factor of ao/factor of an
(+-1/3+-1)/+-1
+- 1/3 , +- 1

Answer 2

What does that mean? I do not get it.

Answer 3

the coef. of X^3 is (1)
the constant num is (1/3)

Answer 4

so factor of the constant + or - / factor of the coef. X^3 + or -

Answer 5

the coef. of X^3 is 1
the constant is 1/3

Answer 6

the factor of 1/3 is 1/3*1 so the factor would be +-{ 1/3, 1}
the factor of 1 is just 1 so the factor would be +-{1}

Answer 7

+-{1/3,1}/+-{1} =+-{1/3,1}
you have 4 numbers {-1/3,+1/3,1.-1}
now use this number in the equation above see which number will give 0 as an answer is would a factor for the long division

Answer 8

Ok, I'll try it. Thank you!

Answer 9

the number that works is rational roots and if you didn't find any all roots are irrational

Answer 10

Is this the function? I cannot decipher (x^3)/(3)-(x^2)/(2)-2x+(1/3) .

@Yaoserr