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Mathematics 21 Online
OpenStudy (anonymous):

consider the experiment of tossing a coin. if the coin shows head, toss it again but if it shows tail, then throw a die. find the conditional probability of the event that 'the die shows a number greater than 4' given that 'there is atleast one tail'

OpenStudy (anonymous):

@FibonacciChick666

OpenStudy (fibonaccichick666):

so how many times are you tossing this coin?

OpenStudy (fibonaccichick666):

do we know, and does it matter?

OpenStudy (anonymous):

Nope, as many times. If outcomes repeat we take them only once. As taken in the sample space.

OpenStudy (anonymous):

We basically, take all outcomes possible. Instead of the no. of tossing. Yeah :-)

OpenStudy (anonymous):

For eg - HH, HT (the two outcomes possible if heads)

OpenStudy (anonymous):

We probably won't go taking HHT or HHHHT kinda. It all gets wrapped in HT :-)

OpenStudy (fibonaccichick666):

well, it is asking for the conditional probability

OpenStudy (fibonaccichick666):

so what does that mean?

OpenStudy (anonymous):

Well, conditional probability means, probability of an event with respect to the happneing of another event

OpenStudy (anonymous):

Here, the condition is there should be a tail and the other part is the die no. should be >4

OpenStudy (fibonaccichick666):

ok so that means, we look at them individually first then combine yes?

OpenStudy (anonymous):

Is it a NCERT question @Abhilash11 ?

OpenStudy (anonymous):

I found the solved one here.Check it out

OpenStudy (anonymous):

Apparently yes

OpenStudy (anonymous):

Yeah well, this doesnt really make any sense so, :-/ I thought of an easier explanation?

OpenStudy (fibonaccichick666):

yep, so we start looking at them independently. so first, what is the probability we get a tails

OpenStudy (anonymous):

@Wxlfz could you help me with this?

OpenStudy (anonymous):

@Abhilash11 Answer is 2/9

OpenStudy (anonymous):

Yeah man. Help me how?? >.<

OpenStudy (anonymous):

Answer is 2/9

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