Question

WILL GIVE A MEDAL PLEASE HELP.
Give the values of a, b, and c needed to write the equation's general form.

2/3(X-4)(X+5)=1



A. A = 2/3; B = 1; C = -20

B. A = 2; B = 2; C = 43

C. A = 2; B = 2; C = -43

Answer 1

ill try to help

Answer 2

2/3* (x^2+5x-4x-20)=1
2/3x+10/3-8/3-40/3=1
2/3x+2/3-40=1

Answer 3

I am thinking they are asking:
General Form of:

Ax^2 + Bx + C = 0

Answer 4

The way you typed it:

\[\frac{ 2 }{ 3 } * (x-4)(x+5) = 1\]

Answer 5

I concur there, and this may be incorrectly typed above?

Answer 6

if not

Answer 7

\[\frac{ 2 }{ 3 } (x^2 + x - 20) = 1\]

\[\frac{ 2 }{ 3 } x^2 + \frac{ 2 }{ 3 }x - \frac{ 40 }{ 3 } = 1\]
\[\frac{ 2 }{ 3 } x^2 + \frac{ 2 }{ 3 }x - \frac{ 43 }{3 } = 0\]

A = 2/3
B = 2/3
C = -40/3

Answer 8

If it is some other equation from mistype, just follow the same procedure.