Find the remainder when f(x) is divided by(x-k)
3x^4-7x^3+5x^2+3x-6;k=2

Question

Find the remainder when f(x) is divided by(x-k) 
3x^4-7x^3+5x^2+3x-6;k=2

fibonaccichick666 · Answer

so can you set up the polynomial division here?

anonymous · Answer

@FibonacciChick666  how would i set it up?

fibonaccichick666 · Answer

well, what is being divided by what is always a good way to start

anonymous · Answer

3x^4-7x^3+5x^2+3x-6 by k?

fibonaccichick666 · Answer

well you are given what k =

fibonaccichick666 · Answer

and if I look it says "f(x) is divided by(x-k)

anonymous · Answer

would it just be 3(2)^4-7(2)^3+5(2)^2+3(2)-6?

fibonaccichick666 · Answer

no, we are dividing not plug and chugging.  We are dividing by x-k, first step is to write that as long division

directrix · Answer

Read the attached items regarding the Remainder Theorem.

As @memirobb   stated

The remainder is the same as f(2) which is:

 3(2)^4 - 7(2)^3 + 5(2)^2 + 3(2) - 6

Crank out that computation and you will have the remainder when f(x) is divided by (x - 2)