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Mathematics 21 Online
OpenStudy (anonymous):

abc has vertices a( 0,0) b( 3,3) c(6,0) find the orthocenter of abc.. a (3,1.5) b (0,0 c ( 1.5 , 1.5 ) d (3,3)

OpenStudy (anonymous):

A? on the basis of diagram that's all. Just a try

OpenStudy (anonymous):

See orthocentre, is the intersection of perpendicular bisectors I suppose?

OpenStudy (anonymous):

that's what im confused on..

OpenStudy (anonymous):

So in this one, its a pretty easy figure. And since it has got something to do with centres, it gets easy with coordinates given

OpenStudy (fibonaccichick666):

It's all about the definition of orthocenter :)

OpenStudy (fibonaccichick666):

this should help :) http://mathforum.org/library/drmath/view/57665.html

OpenStudy (anonymous):

@FibonacciChick666 could you please tell me if the approach ive thought of is genuine or not? :-(

OpenStudy (anonymous):

Yeah :-) Okay so the solution :-D Mind it just by the figure yeah? :P (just tried)

OpenStudy (anonymous):

yes it is thank you (:

OpenStudy (anonymous):

|dw:1418457840773:dw|

OpenStudy (anonymous):

Dont you want the solution?

OpenStudy (anonymous):

this is the triangle

OpenStudy (anonymous):

@FibonacciChick666 Orthocentre, has something to do with the centre of the triangle. Now here, it is the intersection of perpendicular bisectors of the sides. check the side on the x axis. Its mid point is (3,0) orthocentre will obviously pass through this?

OpenStudy (anonymous):

So 3 is a definite point. Now the other point definitely wont be outside the triangle or dont ever say the vertice of a traingle! :P it has to be somewhere around the middle, or inside the triangle :-)

OpenStudy (anonymous):

and so the option that remains is A :-)

OpenStudy (fibonaccichick666):

@Abhilash11 take a step back, The orthocenter is the intersection of the triangle's altitudes.

OpenStudy (anonymous):

Yes yes. Perpendicular bisector = altitide :-)

OpenStudy (anonymous):

thank you guys sm for your help (: I think its a as well o;

OpenStudy (fibonaccichick666):

@Abhilash11 definition Altitude: The distance between a vertex of a triangle and the opposite side. Formally, the shortest line segment between a vertex of a triangle and the (possibly extended) opposite side. Altitude also refers to the length of this segment. Note: The three altitudes of a triangle are concurrent, intersecting at the orthocenter.

OpenStudy (anonymous):

Yes :-) See, right here, the shortest distance will be the perpendicular right?

OpenStudy (fibonaccichick666):

no

OpenStudy (fibonaccichick666):

the tringle is obtuse

OpenStudy (anonymous):

and the shortest distance will be when it intersects its mid point, otherwise there will be a slant, and hence if u imagine you kind of get a hypotenuse. which is greater than a perpendicular :-)

OpenStudy (fibonaccichick666):

no.....

OpenStudy (anonymous):

Umm mm.. ?

OpenStudy (fibonaccichick666):

|dw:1418458333531:dw|

OpenStudy (anonymous):

3,3 cant be there! O.o

OpenStudy (fibonaccichick666):

what is the shortest distance from angle A to BC?

OpenStudy (fibonaccichick666):

draw it

OpenStudy (anonymous):

|dw:1418458455870:dw|

OpenStudy (fibonaccichick666):

that isn't to BC

OpenStudy (fibonaccichick666):

that is to an extension of BC

OpenStudy (fibonaccichick666):

the shortest is simply AB

OpenStudy (anonymous):

Actually :O

OpenStudy (fibonaccichick666):

yeap

OpenStudy (anonymous):

|dw:1418458605644:dw|

OpenStudy (anonymous):

Here should be perpendicular? O.o

OpenStudy (fibonaccichick666):

there yes.

OpenStudy (anonymous):

Okay :-) Thankyou for the void of misconception :-)

OpenStudy (fibonaccichick666):

that also happens to be an isoceles triangle

OpenStudy (anonymous):

Yes :-)

OpenStudy (fibonaccichick666):

|dw:1418458899366:dw|

OpenStudy (anonymous):

wait so was the answer even a guys?

OpenStudy (fibonaccichick666):

nope we need your input

OpenStudy (fibonaccichick666):

we've argued about this long enough. :) So now, we need to know, one, in your own words, what is an altitude? 2, how do you find the orthocenter? and three, is it the vertices or the picture for this triangle?

OpenStudy (anonymous):

Hmm :-)

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