Question

Help with this math problem please.

Answer 1

I doubt even spiderman could read that. Can you type it here please

Answer 2

The circle in the figure below has a radius of r and center at C. The distance from A to B is x, the distance from A to D is y, and the length of arc BD is s. if A=27degrees, s=15, and r=16, find x.

Answer 3

upside down darnit

Answer 4

k can you fillin the letters?

Answer 5

I'm guessing you have to find angle C using arclength and radius.

Answer 6

Then you will know angle D and can go from there.

Answer 7

so we need x, over all

Answer 8

Could law of cosines/sines work, maybe? Just a guess,

Answer 9

let's finish labeling our picture with our knowns first

Answer 10

I'm guessing the solution will involve law of cosines also @Jhannybean

Answer 11

so now, we have an angle and oposite side, part of the side length and no angle for the other, so both @Jhannybean and @msasu25 are right, eventually we will use the law of cosines, but first, we need to find all of thw other tiddly bits.

Answer 12

well that's unfortunate lol so first, if we know the radius, how can we the angle that subtends an arc?

Answer 13

Dos=rtheta?

Answer 14

do s=r(theta) but solve for theta?

Answer 15

what is dos?

Answer 16

cos(x) = rtheta lol

Answer 17

Well,for one, we know that the \(\sf \text{central angle} = \text{intercepted arc}\)

In this case, is would be \(\sf m\angle C = arc~ DB\)

Answer 18

s != rtheta

Answer 19

oh goodness.... my bad. s=Ctheta

Answer 20

where C is circumference

Answer 21

@_lostmathstudent see the revision!!! Don't do extra work

Answer 22

so it would be 15=16(theta) ?

Answer 23

well what is the circumference of the circle?

Answer 24

theta = s/r

Answer 25

oh wait it would be 15/706.853 ?

Answer 26

woah what

Answer 27

yea, something llike that but just leave it as 15/32pi

Answer 28

15/16 = theta

Answer 29

circumference is 15^2pi so it would be 706.858

Answer 30

Just for @FibonacciChick666