Help with balancing equations?
\(CH_3CH_2OH + O_2~ \rightarrow~ CO_2 + H_2O\)
@Abhisar
First of all rewrite the equation as \(\sf C_2H_6O+O_2 \rightarrow CO_2+H_2O\) Now start balancing it
Balance the number of oxygen on both the sides first
Isn't the oxygen already the same on both sides?
Oh yes, balance carbon first..
\(C_2O_2+H_2O\)?
Okay, now lesson no.1....You can not add numbers as subscript. You can only change coefficients like 2C, 3C and not \(\sf C_2~or~C_3\)...getting it?
Ok, so \(2CO_2\)?
Yes, lets write the new equation \(\sf C_2H_6O+O_2 \rightarrow \color{red}{2}CO_2+H_2O\) Now lets balance the number of hydrogens. On left hand side it is 6 while on right hand side it's only 2. What will you do ?
Make it \(\sf 3H_2O\)?
Correct! Yes, lets write the new equation \(\sf C_2H_6O+O_2 \rightarrow \color{red}{2}CO_2+\color{blue}{3}H_2O\) Now finally let's balance the number of oxygen.How many oxygen are there in right hand side?
there are 9 oxygens on the right
How?
whoops miscounted, 7 oxygen 4 in \(\sf 2CO_2\) and 3 in \(\sf 3H_2O\)
\(\huge \checkmark\) Now what will you do to balance it?
because there are only 3 on left hand side.
Remember anything you do but do not disturb counts of other elements....
\(\sf C_2H_6O+3O_2~\rightarrow~2CO_2+3H_2O\)
One thing to note for combustion reactions: 1. balance carbons first, this will help balance the hydrogens right way 2. Balance the hydrogens, you'll be left with an odd number of oxygens (most times) 3. IAfter the Carbons and Hydrogens are balanced, I like to balance the left hand side of the equation for the Oxygens, and work going towards the right.
\(\huge \checkmark\)
YAY!
Well done! ^_^
And note what jhanny said....
Can you help me with one more?
Yep
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