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@ganeshie8 Need help with Tricky Trig identity question. Question is in attached file
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Hint : \[2\cos^2x = 1 + \cos(2x)\]
this is going to take a while
\[8\cos^4x = 2 (2\cos^2x)^2 = 2(1+\cos(2x))^2\]
\[ = 2(1+2\cos(2x) + \cos^2(2x))\] \[ = 2+4\cos(2x) + 2\cos^2(2x)\]
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how do i get the cos4x part?
apply the identity again \[=2+4\cos(2x) + 1+\cos(4x)\] \[=3+4\cos(2x) +\cos(4x)\]
ok so are we allowed to add the angle from (cos2x+1)+(cos2x+1)?
oh wait i see now. cos^2(2x)=cos4x. The angles have a ratio of 1:2
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