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Simplify the expression below and write it as a single logarithm: 3log(x+4)+2log(x-7)-5log(x-2)+log(x^2)
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@triciaal @sexygirl7400
i guess D
\[\log (x^2(x^5-2x^4-71x^3-20x^2+1456x+3136))/ (x-2)^5\]
@sammixboo @TheSmartOne
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Im stumped on this one... maybe @Michele_Laino can help
3log(x+4)+2log(x-7)-5log(x-2)+log(x^2) A number in front of logs means that they are exponents. That means, place all the numbers in front of the logs as exponents log(x+4)^(3)+log(x-7)^(2)-log(x-2)^(5)+log(x^2)
if there is addition between two logs you need to make it multiplication
and if there is subtraction then you need to divide it.
@HugoHuynh please apply this property, first: \[m \log x=\log (x ^{m})\]
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