I need help with inverses, what is the inverse of f if f(x)=3sqrt(x-2)
just swap x and y\[x = 3\sqrt{y - 2}\] and now make y the subject
f-1(x)=2+ In(x)/In(3)
ingore the posted solution from @loveyourlife.... it's wrong
please, keep in mind that for existence of you function has to be: \[x \ge 2\], after that we can write: if y=3sqrt(x-2), then
Okay than I am sorry if it is wrong but I tried to help that's all sorry again !
\[x=f ^{-1}(y)=2+\frac{ y ^{2} }{ 9 }\]
So that would make the answer ?
@loveyourlife you are welcome!!
well go and try to follow the methods provided... Open Study is about helping understanding and not giving answers
@michele_laino if he's wrong what's right?
since @campbell_st is right!, then I will go to explain my answer: now f(x) is: \[y=3\sqrt{x-2}\] please @Claydirt square both sides of that equation
please try, you have to perform this calculus: \[(y)^{2}=(3\sqrt{x-2})^{2}\] please continue @Claydirt
I got f^-1(x)=x^3+2 is that correct ?
No, I think it is a wrong answer, please try to perform the calculus above that I began
left side is equals to: \[y ^{2}\] and right side is equals to: \[9*(...)\] please continue
it is equals to \[9(x-2)\] so: \[y ^{2}=9(x-2)\] please solve that equation in order to find x, and you will get your answer
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