Question

FAN AND MEDAL: Which is a factored form of 216p^3+125q^3?

Answer 1

At first, you can factor out of q^2.

Answer 2

a. (6p+5q)(36p^2+30pq+25q)
b. (6p+5q)(36p^2-30pq-25q)
c. (6p+5q)(36p^2+30pq-25q)
d. (6p+5q)(36p^2-30pq-25q)

Answer 3

ohh it is p^3 and q^3, my bad.

Answer 4

Cant you cube root the whole thing

Answer 5

\(\large\color{blue}{ 5^3=125 }\)
\(\large\color{blue}{ 6^3=216 }\)

Answer 6

\(\large\color{blue}{ 125q^3=5^3q^3=(5q)^3 }\)
\(\large\color{blue}{ 216p^3=6^3p^3=(6p)^3 }\)

Answer 7

Then apply.
\(\large\color{blue}{ a^3+b^3=(a+b)(a^2+ab+b^2) }\)

Answer 8

I would check my rule though, It might be wrong.

Answer 9

so then it would be a?

Answer 10

I messed up my rule. it should say:
\(\large\color{blue}{ a^3+b^3=(a+b)(a^2-ab+b^2)}\)

Answer 11

So it's not A,(as you can see)

Answer 12

ok so then d

Answer 13

it is not -25q at the end, it is supposed to be +25q. No?

Answer 14

I think i put the options wrong. my paper has +25q at the end

Answer 15

so with +25q at the end , (then) D would be correct.

Answer 16

Thank you :)

Answer 17

yw