Question

@Jhannybean

Answer 1

What is one of the products produced when \(\sf Mg(NO_3)_2~and~AlPO_4\) react together?

\(\sf Mg_3(PO_4)_2\\
Al(NO_3)_2\leftarrow\\
Mg(PO_4)_2\\
AlNO_3\)

Answer 2

\[\sf Mg(NO_3)_{2(aq)} +AlPO_{4(s)} \rightarrow \]
Now rememebr, AB + CD --> AD + BC

Answer 3

\[\sf Mg^{2+} = A\]\[\sf NO_3^- = B\]\[\sf Al^{3+} = C\]\[\sf PO_4^{3-} = D\]

Answer 4

Yes, that is one of them :) Is there more than one answer?

Answer 5

No

Answer 6

Well, ok. Can you tell me what the products would be?

Answer 7

\(\sf MgPO_4~+~Al(NO_3)_2\)

Answer 8

\[\sf Mg_3(PO_4)_2(s) +Al(NO_3)_2(aq)\] Yes :)

Answer 9

So in this case since you're only allowed one answer, aluminum nitrate is aqueous , and magnesium phosphate is a solid, so I would think that magnesium phosphate would be the product you re looking for.

Answer 10

@nincompoop

Answer 11

what do you think you should do first @sleepyjess

Answer 12

\(\sf Mg_3(PO_4)_2\)

Answer 13

you have to consider their charges

Answer 14

\(\sf 3(2+) + 2(3-) = 0 \)

Answer 15

does it make sense now?

Answer 16

Yes

Answer 17

wait what

Answer 18

So you found your answer?

Answer 19

I am going with the one I originally picked, but I need help on some more

Answer 20

your first answer is not correct!

Answer 21

why?

Answer 22

count the charges

Answer 23

jhanny gave you the charges for each species
you need to use them

Answer 24

Nin is correct here.

Answer 25

\(\sf Al^{3+} + (NO_3)_2^{-1} \longrightarrow 1(+3) + 2(-1) = -1 \)

Answer 26

+1 sorry HAHA

Answer 27

now count the total charge for the other choices

Answer 28

3(2) + 2(-3) = 0

Answer 29

\[\sf 3Mg^{2+} + 2PO_4^{3-} = 3 (+2) + 2(-3)\]

Answer 30

Yeesss!!

Answer 31

make sure you always include the parentheses, @jhannybean