Question

Bibs helping Bean not drop out

Answer 1

@bibby

Answer 2

♥

Answer 3

Okay, this is gonna take awhile. You prepared?

Answer 4

anything for you

Answer 5

Describe how the graph of y = 2log3(x – 4) + 2 compares to the parent graph. Discuss any changes in the asymptotes, domain, and range.

Answer 6

honestly,. no idea give me a bit

Answer 7

Yep. Me neither, take your time. That's the hardest one.

Answer 8

Wanna skip that one for now?

Answer 9

yes please, I can't really graph logarithmic equations

Answer 10

Solve the equation.

log(x + 7) – logx = 3

Answer 11

this looks n ice

Answer 12

http://www.analyzemath.com/Graphing/GraphLogarithmicFunction.html

Answer 13

It's fine. obviously neither can i.-.

Answer 14

I just need to know what the parent function is for that one. I get stumped there, then I can graph it on a calc.

Answer 15

But yeah, this one for now
Solve the equation.

log(x + 7) – logx = 3

Answer 16

log(x + 7) – logx = 3
\(log(\frac{x+7}{x})=3\)

Answer 17

I guess you can then do 10^3=x+7/x

Answer 18

So wait..

Answer 19

1000=x+7/x

Answer 20

yeah, I'm honestly not positive that's right let's see

Answer 21

wouldn't the x's cancel out?

Answer 22

do you guys use log to mean base 10 or base e
also no, i don't think

Answer 23

both.-. but if not specified then 10

Answer 24

because wolfram says x= 7/e^3-1 which is weird

Answer 25

want the choice options

Answer 26

yeah

Answer 27

3.5
142.7
0.0070
0.0707

Answer 28

HAHA I DID THE LAST ONE ALL ON MY OWN

Answer 29

I'll write it out

Answer 30

And okay :D I'm so proud of myself. I could fail and not care because i did the last one. ANYWAY

Answer 31

\(\huge \frac{x+7}{x}=1000\)
1000x=x+7
999x=7
x=7/999=0.00700700...

Answer 32

I meant C

Answer 33

wait but how did you get 99+? Just subtracting the 1x? And then okay. I see it nvm

Answer 34

yeah

Answer 35

Write the expression as a single logarithm.

5logby + 6logbx (1 point)

Answer 36

Uhh hang on I'll write the equation.

Answer 37

i think I get it

Answer 38

\[5\log_{b}y +6\log_{b}x \]

Answer 39

\(log_ba^n=nlog_ba\)

Answer 40

5nlogba?

Answer 41

it's starting to sound like we're talking clingon

Answer 42

talk dirty to me in klingon please
5logby + 6logbx = logby^5 + logbx^6

they have common base
\(log_b(y^5x^6)\)

Answer 43

So would that be my final answer? Dx

DaneHchugh

Answer 44

what does that mean
yes

Answer 45

"If you want"

Answer 46

oh, nothing hotter than consensual relations

Answer 47

XD omg.

Answer 48

<3

Answer 49

<3 one moment

Answer 50

leghlaHbe'bogh Hol 'oHbe' sexy

Answer 51

uh brb translator

Answer 52

USE THE BING ONE

Answer 53

omfg it comes out so wrong! I said the language is not sexy, and if you flip it around it says "a blind man, and language is not sexy.

Answer 54

I am a blind man
you could make klingon work bbygurl

Answer 55

WELL ITS N?OT

Answer 56

:( don't yell at me

Answer 57

.-. I'm kidding

Answer 58

me too

Answer 59

Okok this is getting hard again hang on

Answer 60

hehehehe

Answer 61

HANG ON LOL GET IT

Answer 62

i dont

Answer 63

I'm getting frustrated hang on.

Answer 64

you better get used to that if we become item

Answer 65

XD shut up bibs

Answer 66

:X

Answer 67

The half-life of a certain radioactive material is 68 hours. An initial amount of the material has a mass of 641 kg. Write an exponential function that models the decay of this material. Find how much radioactive material remains after 4 hours. Round your answer to the nearest thousandth. (1 point)

Answer 68

\(y=a(1-r)^x\)
\(y=641(1-r)^{68}\)
a=initial amount
r-rate
x-time

Answer 69

I'm not sure what r would be

Answer 70

Eh, I got that much right. I'll do my final tomorow

Answer 71

let's do more stuff wehile we're here

Answer 72

More math?

Answer 73

I was hoping hot internet sex while I pretend to be a cute young lifeguard boy that noticed you in summer camp but math is good too

Answer 74

._. lifeguards are almost all shallow

Answer 75

did I dig up old wounds

Answer 76

No I can't swim

Answer 77

Just jealous of those who can

Answer 78

Lets take an intermission of math for a second though because my head hurts

Answer 79

ok, we'll talk about everything that isn't math

Answer 80

like i have three dogs

Answer 81

I have 3-3 dogs

Answer 82

0?

Answer 83

WHY

Answer 84

idk, my parents aren't pet people
I want to get a cat

Answer 85

I want to be a vet

Answer 86

give me horse tranquilizer

Answer 87

Deal

Answer 88

what do I offer you

Answer 89

This tutoring stuff

Answer 90

I do that out of the goodness of my heart also this is the only female interaction i get

Answer 91

Well, i'm here. BIbs can i ask you somethin?

Answer 92

anything
you don't have to ask permission

Answer 93

Is that you in your picture?

Answer 94

yes

Answer 95

Yeeet you say you're a girl cx

Answer 96

the 2 aren't mutually exclusive

Answer 97

Don't riddle me.

Answer 98

I'm just a bored old man that wants to crossdress but doesn't because he lives with his parents