Question

break up

Answer 1

\[\frac{ s }{ (s+1)^2+1 }\]

Answer 2

the answer is \[\frac{ s+1 }{ (s+1)^2+1 }-\frac{ 1 }{ (s+1)^2+1 }\]

Answer 3

Is there a algebraic way to get there

Answer 4

@zepdrix

Answer 5

partial fraction decomposition possibly

Answer 6

are you doing leplace transforms?

Answer 7

ha ha yup @DanJS are you in the same boat?

Answer 8

no, i took Differential equations a couple semesters ago and did well

Answer 9

and the s variable gave it away t space to s space transform

Answer 10

yea partial fractions ?

Answer 11

\(\LARGE\color{black}{ \frac{s}{(s^2+1)+1} }\)

\(\LARGE\color{black}{ \frac{s+1-1}{(s^2+1)+1} }\)

\(\LARGE\color{black}{ \frac{s+1}{(s^2+1)+1} -\frac{1}{(s^2+1)+1} }\)

it seems like you did this.

Answer 12

that is true too

Answer 13

if i recall the inverse transforms of those go to sin(kt) and cos(kt) in t space

Answer 14

but if you are doing a laplace, isn't that a given formula usually?

Answer 15

lol @SolomonZelman I didn't think that way. It is so awsome

@dan I don't think I can use partial frac here

Answer 16

I mean there is no need in calc to do this.

Answer 17

I use it many times, and call it the magic zero.

Answer 18

but yea add a number substract a number is all ya did.

Answer 19

But like I said, for an invers laplace transform, i don't think any modification is necessary