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Mathematics 19 Online
OpenStudy (anonymous):

An architect for a golf course wants to plan a sand trap that passes between a tree and a cart path. Using these as the focus and directrix, how can the architect plan a parabolic sand trap that will be equidistant from the tree and the cart path at all times? Describe your method in full sentences.

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

The cart path can be a directix and tree the focus

ganeshie8 (ganeshie8):

|dw:1418566316344:dw|

OpenStudy (anonymous):

I would help but I have no clue.

ganeshie8 (ganeshie8):

Suppose the vertex of parabolic sand trap is at origina and the parabola opens up. Say \(F = (0, a)\), then the equation of drectrix line would be \(y = -a\). Let \(P(x,y)\) be any point on the parabola and \(M\) be the perpendicular from \(P\) to the directix line : |dw:1418566622367:dw|

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