Question

What are the discontinuities of the function f(x) = the quantity x squared minus 16 over the quantity 4x plus 24 ?

Answer 1

\[f(x) = (x-16)^2/(4x+24)\]

so factor the numerator and denominator

Answer 2

well factor both the numerator and denominators

Answer 3

\[\frac{ (x-4)(x+4) }{ (4)(x+6) }\]

Answer 4

\[\frac{x^2 - 16}{4x + 24}\]

you will find a common factor....

but 1st solve

4x + 24 = 0

to find the discontinuity

Answer 5

the denominator can't equal zero so set the denominator equal to 0

Answer 6

4(x+6) = 0

Answer 7

x = -6

Answer 8

Wait so are you saying the discontinuity is -6?

Answer 9

yes

Answer 10

you're correct @nicjohns it is not 0... that's why you shouldn't post answers

Answer 11

Thank you!!!