College Algebra: reviewing for Final Exam!
If f(x)=x^2-9 and g(x)=x-3, then (f/g)(5)= ?

Question

College Algebra: reviewing for Final Exam!
If f(x)=x^2-9 and g(x)=x-3, then (f/g)(5)= ?

anonymous · Answer

$$f(x)=x ^{2}-9$$
and
$$g(x)=x-3$$
then $$(\frac{ f }{ g })(5)$$

solomonzelman · Answer

that was a record glitch just now for me.

solomonzelman · Answer

Anyways, when you say,  $\Large\color{black}{   \frac{\color{red}{f}}{\color{blue}{g}}(x)}$,
you are basically saying,

$\Large\color{black}{   \frac{\color{red}{x^2-9}}{\color{blue}{x-3}}(x)}$

anonymous · Answer

Yes

solomonzelman · Answer

you can divide by (x-3) on top and bottom, (knowing how to factor the  $\large\color{black}{  x^2+9}$.
and then plug in 5 for x.

solomonzelman · Answer

I mean -9, not +9. ***

solomonzelman · Answer

$\Large\color{black}{   \frac{\color{red}{f}}{\color{blue}{g}}(x)=\frac{\color{red}{x^2-9}}{\color{blue}{x-3}}}$

anonymous · Answer

|dw:1418590202446:dw|
Like this correct?