Find an equation of a line through (−2, −3) with M=1/2

Question

solomonzelman · Answer

$\large\color{black}{    (y-y_1)=m(x-x_1)                }$

solomonzelman · Answer

for example, if I was asked:
`Find an equation of a line through (-3, 2) with M=1/3`
the this is what I would do:

$\large\color{black}{    y-y_1=m(x-x_1)                }$

$\large\color{black}{    y-2=\frac{\LARGE 1}{\LARGE3}(x-(-3)~)                }$

$\large\color{black}{    y-2=\frac{\LARGE 1}{\LARGE3}(x+3)                }$

$\large\color{black}{    y-2=\frac{\LARGE 1}{\LARGE3}x+1                }$

$\large\color{black}{    y=\frac{\LARGE 1}{\LARGE3}x+1 +2              }$

$\large\color{blue}{    y=\frac{\LARGE 1}{\LARGE3}x+3              }$

anonymous · Answer

what did you do on your 3rd step @SolomonZelman

solomonzelman · Answer

I know that:  $\large\color{black}{ a-(-b)=a+b }$ correct?

anonymous · Answer

sorry i meant 4th i understood the 3rd one

solomonzelman · Answer

yes, so I just expanded the parenthesis on the right side:

$\large\color{black}{ \frac{\LARGE 1}{\LARGE 3}(x+3) \
\
\Longrightarrow  (\frac{\LARGE 1}{\LARGE 3})x+(\frac{\LARGE 1}{\LARGE 3})3 \
\
\frac{\LARGE 1}{\LARGE 3}x+1  }$

solomonzelman · Answer

makes sense?

solomonzelman · Answer

if you have any questions regarding your problem, I can surely help you./

anonymous · Answer

yes thank you

solomonzelman · Answer

yes, you have questions, or yes, you are good.... ?  ;)