Question

Identify sqrt(2) as either rational or irrational, and approximate to the tenths place.

Answer 1

@Jhannybean @Nnesha

Answer 2

Before you answer this question, am i correct for this one?:
Solve x^2 = 121.
=, ±11

Answer 3

Because 11^2 can be -11, 11 so its both ways.

Answer 4

Am i wrong?

Answer 5

you are correct about \(\large\color{black}{ x^2=121 }\) that. \(\large\color{black}{ x=\pm11 }\)

Answer 6

OMG!!!!!! you have been gone for \(\small\sf\color{red}{SOO}\) long!

Answer 7

k

Answer 8

the picture I posted about real numbers numbers should help with the question of the post;)

Answer 9

I wrote "numbers" twice;) lol

Answer 10

XD okay ty.

Answer 11

yes, so is \(\large\color{black}{ \sqrt{2} }\) a rational, or an irrational number?

Answer 12

Irrational

Answer 13

yes:)

Answer 14

and the approximation of \(\large\color{black}{\sqrt{2} }\) to the nearest 10th?

Answer 15

1.5?

Answer 16

we know that:
\(\large\color{black}{\sqrt{2} \approx 1.4142... }\)
(symbol \(\large\color{black}{\approx }\) means "approximately equal)

Answer 17

when you round a \(\large\color{black}{1 }\) does it become a \(\large\color{black}{10 }\) or a \(\large\color{black}{0}\) ?

Answer 18

0

Answer 19

Oh wait

Answer 20

yes, so when you say
\(\large\color{black}{\sqrt{2} \approx 1.41 }\)

then is it \(\large\color{green}{\sqrt{2} \approx 1.5 }\) or \(\large\color{blue}{\sqrt{2} \approx 1.4 }\) ?

Answer 21

1.4

Answer 22

yup, there you go!

Answer 23

ty

Answer 24

np

Answer 25

i got one more

Answer 26

sure

Answer 27

Ill tag you.

Answer 28

okay;)