Question

@DanJS

Answer 1

do you need help?

Answer 2

no sorry I don't know this yet.

Answer 3

@DanJS

Answer 4

hi

Answer 5

\[\int\limits (x^3 - 6x)dx = \frac{ 1 }{ 4 }x^4 - 3x^2\]

Answer 6

then figure F(3) - F(0)

Answer 7

-27/4
about - 6.75

Answer 8

what was the answer we use for the last problem? the summation one?

Answer 9

-3.938

Answer 10

hmm, something was missing there, it should be close to this answer

Answer 11

@DanJS

Answer 12

is this question right? @DanJS

Answer 13

@DanJS this question

Answer 14

is this it for this question? like its done?

Answer 15

yeah this is correct

Answer 16

just computing the def integral

Answer 17

so what is happening with the other question? is that one wrong?

Answer 18

yeah , it should come out at least somewhat close to this one

Answer 19

oh..

Answer 20

the sum approximates the integral

Answer 21

ill just put it up again then.