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Chemistry 16 Online
OpenStudy (anonymous):

What is the pH of a 1.2 x 103 M solution nitric acid solution?

OpenStudy (nechirwan):

pH=-loge[H] =-loge(1.2x10^-3) pH=2.9

OpenStudy (nechirwan):

its 10^-3 not 10^3 lol

OpenStudy (anonymous):

Ok thanks

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