Alg 2 help? Will fan, medal and testify.
Simplify the expression \[\frac{ -5+i }{ 2i }\] Show your work
i suggest that you multiply top and bottom by i first
what do you mean testify?
\(\large \frac{-5+i}{2i}=\large \frac{(-5+i)i}{-2}\)
\[\frac{ (-5i+i^2 }{ 2i}\] Like this? And I meant a testimonial
Take it from there....
look at my reply i said top and bottom by i not just top
Why would multiplying the bottom by i remove the i? Wouldn't it just stay the same because 1xanything= the other number?
because \(\large i^2=-1\) you need to rationalize the bottom
\[\frac{ -5i+i^2 }{ -2}\] Ok so thats what it would end up as then?
i^2=-1 you have i^2 on top and simplify more
\[\frac{ -5i-1 }{ -2 }\] which would then simplify to \[-5i+\frac{ 1 }{ 2 }\]?
you have separated the fraction but not correctly 5/2 i +1/2
Oh ok. Sorry, simple mistake I should't have missed. So is that the final answer?
yes! it preferably to right a complex number in this form z=a+bi so 1/2+5/2 i but either ways is correct
Thanks a million! You helped a lot!
no problem
I will post ur testimony later tonight, my family is yelling for me to get upstairs for family night! Thanks again!
No worries about that^_^
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