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OpenStudy (anonymous):
Balance the following nuclear equation and write the missing symbol with numbers. Give the type of radiation it has undergone. ^210Po -> X + ^4v2He
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OpenStudy (anonymous):
\[^{210}Po \rightarrow X + ^{4} _{2} He\]
OpenStudy (anonymous):
@ganeshie8
OpenStudy (surry99):
I can help if you like.
OpenStudy (anonymous):
yes please @surry99 I would really appreciate it!!
OpenStudy (surry99):
in all reactions, mass must be conserved...agreed?
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OpenStudy (anonymous):
agreed!
OpenStudy (surry99):
ok, are you familiar with the term nucleon?
OpenStudy (anonymous):
yes i am
OpenStudy (surry99):
great...so on the left you have a total of how many nucleons?
OpenStudy (surry99):
and...how many protons does Po have?
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OpenStudy (anonymous):
210 & 84 protons correct?
OpenStudy (surry99):
ok so put the 84 at the bottom left of Po...
OpenStudy (anonymous):
okay did that
OpenStudy (surry99):
Now you know the number of protons on left and right must balance and the number of nucleons...
For protons we have :
84 = ? + 2 so what is ?
OpenStudy (anonymous):
82?
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OpenStudy (surry99):
yes indeed ....now for the nucleons:
210 = ?? + 4...?? equals....
OpenStudy (anonymous):
wait so, so far is this correct? |dw:1418610767560:dw|
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