What is ( (tan^2)x)(2x)=3
\[2x \tan^{2}(x) = 3\] is that it?
Might be. I'm looking at it like O______________________o
I think you have to use \(\cos ^2x = 1-\sin^2 x\)
But even then I'm not completely sure of the trick here.
Are we trying to solve for x in this problem?
It's a non-linear problem, and is not likely to have an elementary solution. Try numerical methods.
@Asiah321 could you confirm the equation? what @DanJS posted can not be solved algebraically
\[(\tan ^{2}x) \space (2x) \space = 3\]
\[(tanx)^{2} \space (2x) \space =3\]
You can't actually solve this by hand because you can't get x alone tan^2 x means (tanx)^2 If you want to get x, you need a calculator You would either have to graph y = (tanx)^2*2x and y = 3 and find where they intersect Or graph y = (tanx)^2*2x - 3 and find where it hits the x-axis
There are 4 roots between 0 & 2pi. The first one is around 0.9093 rad.
Newton's method would come handy for this, or even bisection method.
Right
I agree with that too. Whichever methods allow you to approximate roots
Newton's method might be a drag though since you would need to do it for each root
i just guessed that was his question, i could be wrong
Just using a calculator straight out seems to be the easiest method here You would need a calculator for newton's method in any case
For those interested, I graphed it as suggeste by @Miracrown, it gives roots at 0.9,2.5,3.7,and 5.8 between 0 and 2pi, for those who would give it a try.
Yes, I agree ^
and for the Newton fans, y'(x)=2tan^2(x)+4x tan(x)/cos(x)^2
@DanJS we're all in the dark, and you're the only one with a candle. :) It's up to @Asiah321 to correct your best interpretation if it's not correct.
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