Question

Solve for "x".
2*3^x =7*5^x.

Answer 1

1st when you typing a math problem always use the stare ( * ) when multiplying because in algebra x is a variable.

Answer 2

star*

Answer 3

sorry its late

Answer 4

oh sorry thanks

Answer 5

yeah so after you retype the question ill help

Answer 6

show me first two step and im good dude.

Answer 7

ok

Answer 8

well the first step is to get x by itself on one side

Answer 9

Is your problem : \(2\cdot 3^x=7\cdot 5^x\) ?

Answer 10

yes

Answer 11

1st devide 7 by 2

Answer 12

The Answer is x= -2.45

Answer 13

This is a little complicated, but isolate 1 of the 2 functions with an x

Answer 14

divide* jeez

Answer 15

yes it is

Answer 16

Could you just type up entire solution in one go then actually?

Answer 17

here use this
http://www.mathpapa.com/algebra-calculator.html

Answer 18

should work

Answer 19

doesn't work

Answer 20

Actually!!!

Answer 21

Start by taking the log of both sides.

Answer 22

thats weird it always does

Answer 23

\[2\cdot 3^x = 7\cdot 5^x\]Taking the log of both sides..\[\log(2\cdot 3^x) = \log(7\cdot 5^x)\]With the properties of logs, you know that \(\log(a) +\log(b) = \log(ab)\) So apply this rule.

Answer 24

Apply this rule to both sides to separate the functions. \[\log(2) +\log(3^x) = \log(7) +\log(5^x)\]Now you can apply the power rule to log functions here, also. \[\log(x^n) = n\log(x)\]

Answer 25

Are you with me so far?

Answer 26

thank you! :)