Ask your own question, for FREE!
Geometry 16 Online
OpenStudy (anonymous):

The price of a cheeseburger is listed for 10 different restaurants. Which measure would give the most accurate representation of the average price of a hamburger? ($2.50,2.00,3.00,8.50,2.75,3.00,2.50,3.50,2.75,1.00) 1. mode 2. median 3. range

OpenStudy (hunus):

Which do you think it is?

OpenStudy (anonymous):

I think all of them cannot be the answer.

OpenStudy (hunus):

One of them is the correct answer.

OpenStudy (anonymous):

Because we have too many modes

OpenStudy (anonymous):

And for median, we have 8.50. So I think median couldn't be the answer, too

OpenStudy (anonymous):

For range, it seems odd because we get 7 something

OpenStudy (hunus):

$8.50 is expensive for a hamburger. It is an outlier. But it is still part of our data set so we can't just get rid of it.

OpenStudy (anonymous):

Yeah.

OpenStudy (hunus):

Range doesn't really tell us anything about the values of our data. It just tells us how far apart items in our data are.

OpenStudy (anonymous):

Oh that sounds correct. So we can get rid of Range

OpenStudy (hunus):

Yup.

OpenStudy (anonymous):

Then we have mode and median

OpenStudy (hunus):

What about mode and median?

OpenStudy (hunus):

What does mode tell us about our data?

OpenStudy (anonymous):

It tells us which data is most frequent

OpenStudy (anonymous):

But we have two modes.

OpenStudy (hunus):

Do our modes take into account all of the prices in our data set?

OpenStudy (anonymous):

Nope (?)

OpenStudy (hunus):

Then the mode can't very well give us an average representation of ALL of our data

OpenStudy (anonymous):

oh yeah. so the answer is median? But I want to make sure that whether the median shows us the average price of a hamburger

OpenStudy (anonymous):

Since we have an outlier, I wonder it could show the average price of a hamburger or not

OpenStudy (anonymous):

This is nasty question!

OpenStudy (hunus):

It will. The outlier will affect our data, but if you gave someone the average price of a hamburger in that city without the individual prices it would be deceptive because all of the data points don't lie near the median.

OpenStudy (hunus):

In a perfect situation (in a "nice" data set), all of the data lies more or less around the median. However, in some situations, an outlier will pull the median one way or another.

OpenStudy (anonymous):

Oh so for mode, since we have two modes, mode can't show us the average price. For range, it just shows us how far they are. And for median, it shows us the average price?

OpenStudy (hunus):

Median is synonymous with the average of a set of data.

OpenStudy (hunus):

Even if we have one mode, the mode only takes into consideration the items that occur more than once.

OpenStudy (hunus):

So it isn't very helpful for determining something like the average

OpenStudy (anonymous):

Oh. the mode only takes into consideration the items that occur more than once. That is clear. Thank you. Umm I have the farther question. sorry. Isn't the mean the synonym for average? Does mean can be the answer, too? Because I chose "mean", and I got wrong.

OpenStudy (hunus):

Oh goodness. I don't know why I was mixing up median and mean

OpenStudy (hunus):

However, the median would still be the correct answer

OpenStudy (anonymous):

Could you explain why?

OpenStudy (anonymous):

Median is the one you get when you add all the data and dived them up. right? Median is just the middle number?

OpenStudy (hunus):

It would be a little more accurate to say "Which - of the available- measures would give the most accurate representation of the average price of a hamburger?"

OpenStudy (hunus):

Mean is when you add them up and divide them. Median is the middle value of our set

OpenStudy (anonymous):

Oh yeah. But I am still confused because of the mean. Could you explain why median is the answer for this question?

OpenStudy (hunus):

The median of a set gives the most correct average of a set when the values in the set are uniformly distributed - so that there aren't a lot of outliers.

OpenStudy (hunus):

|dw:1418626287912:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!