Question

sin(cosx)sinxdx =

Answer 1

anti derivative

Answer 2

u=cosx and -du=sinx

Answer 3

then what?

Answer 4

anyone?

Answer 5

well lets look at an example: http://tutorial.math.lamar.edu/Classes/CalcI/SubstitutionRuleIndefinite.aspx

Answer 6

i'm not too sure about the formatting of your equation, could you clean it up?

Answer 7

I know the concept but i dont know how the person got the answer http://www.math.rutgers.edu/~sferry/MA135F14/135-f14/Fall2009ANS.pdf
3b

Answer 8

i assume that you know roughly how to choose a substition that will work for this particular problem. seeing as we need to encapsulate both the dx, cosx, and sinx in 2 substitutions
a u an du.

Answer 9

yes i understand that concept

Answer 10

i dont understand sinu(-du) equals cosu+c

Answer 11

du = -sin(x)dx works well because we can easily get rid of that extra sin(x) and the negative makes it turn into an easy cos(x) when we actually anti-derive, u is cosx, well b/c that would result in a simple sin(u)

Answer 12

oh well the negative comes out of -du, to become -sin(u)du. whats the anti-derivation of -sin?

Answer 13

(anti-derive and integral are essentially the same right?)

Answer 14

i understand

Answer 15

i really appreciate all your work

Answer 16

but couldnt it be du(u)du since du=sin @3abf6277

Answer 17

ah du ONLY = sinx(dx), it doesnt apply to the front sin(x)

Answer 18

the reason? because you literally defined du as -sin(x)dx

Answer 19

no du as just sin(X)