ok stuck yet again. I need to find the general solution of the linear system: $${\huge{\{}} \left(\begin{matrix}x_1'=-5x_1-6x_2 \ x_2'=2x_1+2x_2\end{matrix}\right)$$
@ganeshie8 @Marki I'm in need of a nice hint

Question

ok stuck yet again.  I need to find the general solution of the linear system: $${\huge{\{}} \left(\begin{matrix}x_1'=-5x_1-6x_2 \ x_2'=2x_1+2x_2\end{matrix}\right)$$
@ganeshie8 @Marki I'm in need of a nice hint

anonymous · Answer

$${\huge{\{}} \left(\begin{matrix}x_1'=-5x_1-6x_2 \ x_2'=2x_1+2x_2\end{matrix}\right)$$

fibonaccichick666 · Answer

So I can find A but the issue is I don't have x(0) so I'm a bit confused.  Is there a way other than Laplace transforms?

ganeshie8 · Answer

@Marki

ganeshie8 · Answer

if i remember, we find eigen values and eigen vectors and cookup the general solution ?

fibonaccichick666 · Answer

I mean I can find those no problem, but I really can't figure out the approach here.

anonymous · Answer

yes yes
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