Question

derivative of sqrt(x^2 + (sinX)^2)

Answer 1

\[\sqrt{x^2 + (sinX)^2}\] this?

Answer 2

I looked the answer up, and it's wrong, just not sure why...

Answer 3

looks like you forgot to cancel the 2

Answer 4

other than that at first glance I don't see anything else wrong. I do recommend using substitutions for the chain rule though

Answer 5

what are substitutions, do you ever start from the innermost and work outward?

Answer 6

wolfram says I'm wrong http://www.wolframalpha.com/input/?i=derivative+of+sqrt%28x%5E2+%2B+%28sinX%29%5E2%29

Answer 7

ignore my last, ok let's do it then

Answer 8

have to run, can you work through the steps for me?

Answer 9

\[f(x)=\sqrt{x^2 + (sinx)^2}\]

Answer 10

this takes 2 minutes come on

Answer 11

literally have three minutes

Answer 12

let u=x^2+sin^2x

Answer 13

du=?

Answer 14

then you have \[f(x)=u^\frac{1}{2}\]

Answer 15

f'(u)=?

Answer 16

then backsub

Answer 17

don't forget make \(r=sinx\) then dr=cosx

Answer 18

so you get du=?...dr

Answer 19

then that's it

Answer 20

btw, http://www.wolframalpha.com/input/?i=derivative+of+%28x%5E2+%2B+%28sin%5E2x%29%29%5E%281%2F2%29

Answer 21

when you put in two different sized x's it did the partial with respect to x

Answer 22

You learn about those in calc III