Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (eric_d):

By using differentiation of product rule, find dy/dx of y=x cos x

OpenStudy (eric_d):

@ganeshie8

OpenStudy (callisto):

\[\frac{dy}{dx}=\frac{d}{dx}x\cos x = x\frac{d}{dx}\cos x+\cos x\frac{d}{dx}x\]

OpenStudy (callisto):

Product rule: \[\frac{d}{dx}uv=u\frac{d}{dx}v + v\frac{d}{dx}u\]

OpenStudy (eric_d):

Got it! Thanks @Callisto

OpenStudy (callisto):

You're welcome!

OpenStudy (eric_d):

How to do this? y=x^2 sin 2x

OpenStudy (eric_d):

|dw:1418650304968:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!