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How to solve e^-x=5?
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Are you familiar with logarithms?
sorta, mostly natural log and base 10.. i forget e. @swagmaster47
You can take the log of both sides so you have\[-xlog(e=\log(5\]
Hi there! I am going to give a similar example. \[e^{2x}=2\]\[\ln(~e^{2x}~)=\ln(2)\]\[2x~\ln(~e)=\ln(2)\]\[2x~(1)=\ln(2)\]\[2x=\ln(2)\]\[x=2/\ln(2)\]
The North Korean president is good in maths!
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IF, lol:)
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