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Mathematics 17 Online
OpenStudy (anonymous):

Use graphs and tables to find the limit and identify any vertical asymptotes the function. limit of 1 divided by the quantity x minus 10 squared as x approaches 10 The answer I got was negative infinity, x = 10. Can someone just check to see if that's right?

OpenStudy (anonymous):

@phi

OpenStudy (phi):

can you post these as equations? it's tough to decipher when spelled out. \[ \lim_{x\rightarrow 10} \frac{1}{(x-10)^2}\] ?

OpenStudy (anonymous):

Yes that's what it looks like. My bad.

OpenStudy (phi):

it approaches divide by 0, so infinity. but no matter what x is , (x-10)^2 is positive, so I don't see how to get negative infinity.

OpenStudy (anonymous):

So infinity would be positive?

OpenStudy (phi):

yes

OpenStudy (anonymous):

The vertical asymptote is x = 10 though?

OpenStudy (anonymous):

@phi

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (phi):

yes

OpenStudy (anonymous):

Thank you

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