Question

The Century club runs the concession stand during football games. They sell snacks and drinks.

50 snacks and 180 drinks will sell for $320.
75 snacks and 100 drinks will sell for $225.
How much does each drink sell for?

Answer 1

Let x represent the cost of a snack
Let y represent the cost of a drink

Our equations are gonna be in terms of cost since that is what we are interested in
Now lets write a formula for both situations:
50x+180y=320
75x+100y=225

Now in order to solve for x and y you can use a multitude of methods.
Which one you familiar with?/
Substitution, elimination, matrices?

Answer 2

either substitution or elimination

Answer 3

Lets do substitution... I think its easier and lets write the second equation in terms of y
75x+100y=225
100y=225-75x
divide by a 100
\[y=\frac{225}{100}-\frac{75}{100}x\]
y=2.25-.75x

Answer 4

is it 1.5 ?

Answer 5

Now replace the y in the first equation with 2.25-.75x
So 50x+180y=320
Which becomes
50x+180(2.25-.75x)=320
Solve for x

Answer 6

lol didnt have time to solve it ....
Running out hmmmm
@Jhannybean Can you finish this off for me I gotta run out and my family .... is gonna kill me

Answer 7

Bump your quesion ... if not i will be back in 20 minutes

Answer 8

i did.

Answer 9

Thank you tho , ill be on .

Answer 10

back

Answer 11

50x-135x+405=320
-85x+405=320
-85x=-85
x=1
y=2.25-.75x
y=2.25-.75(1)
y=1.5
Yes you were correct