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OpenStudy (junyang96):
Probability http://prntscr.com/5hsuto
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ganeshie8 (ganeshie8):
Where are you stuck at ?
OpenStudy (junyang96):
second
OpenStudy (junyang96):
I'm not sure if repetition is allowed. Question doesn't say anything
ganeshie8 (ganeshie8):
three `different` digits
so clearly repitition is not allowed for part b
OpenStudy (ikram002p):
u have 6 numbers ,how many number u can represent ?
how many numbers u can represent if it have different digits ?
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OpenStudy (ikram002p):
note both cases ,u need 3 digits only
OpenStudy (junyang96):
I don't get it. Let's start over again. I'm guessing my sample space to be 6P3. Is that correct?
ganeshie8 (ganeshie8):
total 3 digit numbers that can be formed from given set of numbers = 6x6x6 = 6^3
ganeshie8 (ganeshie8):
total 3 digit numbers without the digit 5 would be 5x5x5 = 5^3
take the ratio for part a
OpenStudy (junyang96):
oh i see
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OpenStudy (junyang96):
Let me draw this|dw:1418817858514:dw| So for each column I have to choose one out of the 6 number to put in. Right? For P(B)=(1/6)*(1/5)*(1/4)=1/120
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