Question

I need help I'll fan and medal!

Which ordered pair makes the inequality true?

x + 2y > 8

Answers:
A. (–13, 0)
B. (–2, 4)
C. (0, 4)
D. (11, –1)

Answer 1

Thank you @ElonaSushchik

Answer 2

Already Fanned and Gave you your Medal.

Answer 3

Just remember: (x,y)
Ex: A. -13 + 2(0) is greater than 8
-13 is not greater than 8, so this is not true

Answer 4

You're welcome.

Answer 5

Thank you @Hally85

Answer 6

Just plug in each ordered pair to see if it makes the inequality true.
For A, -13 would be x and y would be 0.
x + 2y > 8
Plugging the ordered pair for A in.
-13 + 2(0) > 8
-13 + 0 > 8
-13 > 8 <--- This is not a true statement. So, we'd have to keep trying the different pairs until we got a true statement.
For B, x would be -2 and y would be 4.
x + 2y > 8
-2 + 2(4) > 8
-2 + 8 > 8
6 > 8 <--- Not a true statement. So we need to move onto C.
For C, x would be 0 and y would be 4.
x + 2y > 8
0 + 2(4) > 8
0 + 8 > 8
8 > 8 <--- This is also not true because 8 cannot be greater than itself.
Moving onto D.
For D, x would be 11 and y would be -1.
x + 2y > 8
11 + 2(-1) > 8
11 -2 > 8
9 > 8 <--- This is true. 9 is indeed greater than 8.
In conclusion, D is the only ordered pair that makes the inequality true. Not A, B, nor C.
The answer is D. (:

Answer 7

Thank you @BunnyBree ! :D

Answer 8

You're welcome. :D Do you understand how to do problems like this now? It's fairly simple. (:

Answer 9

Yes I do, Thank you for taking your time to explain You've helped me very much.