Question

Find the x- and y- intercepts of the line that passes through the given points. (-5,-5) and (5,-1)

Answer 1

calculate the slope first

Answer 2

@DanJS The slope is 2/5 I think?

Answer 3

correct

Answer 4

now use that slope, and one of the points in the point slope forumula

Answer 5

y - y1 = m(x-x1)

Answer 6

\[
\frac{-5-(y_1)}{-5-(0)} = \frac{-5-(-1)}{-5-(5)}
\]

Answer 7

@DanJS which number do i plug in?

Answer 8

This helps to find \((0,y_1)\), which I guess it the \(y\) intercept.

Answer 9

(x1,y1) = any of the 2 points given

Answer 10

y - (-1) = (2/5)(x - 5)

Answer 11

y + 1 = (2/5)x - 2

Answer 12

when x = 0 what is y?

Answer 13

0? idk

Answer 14

For the intercepts, you set x=0 and find y, and set y=0 and find x

(0,y)
(x,0)
in
y+1 = (2/5)x - 2

Answer 15

does this look correct?
y+1=(2/5)(0)-2
y+1=(2/5)-2
y+1-1=(2/5)-2-1
y=2/5-1

am i on the right track or no?

Answer 16

When x = 0 you get

y + 1 = (2/5)(0) -2

y = -3

Answer 17

2/5 times 0 is zero

Answer 18

ok sorry missed that

Answer 19

So the point (0,-3) is the y intercept

Answer 20

Now set y = 0 and find x in

y + 1 = (2/5)x - 2

Answer 21

0+1=2/5(x)-2
1=2/5(x)-2

right track?

Answer 22

yes, now multiply everything by 5 to get rid of that fraction

Answer 23

5=x-2

Answer 24

5 = 2x - 10

Answer 25

oops just realised that

Answer 26

so x = 15 / 2

Answer 27

ok so now it would be
5=2x-10
5+10=2x-10+10

Answer 28

yes, then divide by 2

Answer 29

7.5

Answer 30

so the point (15/2 , 0) is the x intercept

Answer 31

yeah or 7.5

Answer 32

ok thank you so much!!

Answer 33

summary:

1)find the equation for the line
2) set x = 0 and find y ; (0,y)
3) set y = 0 and find x ; (x,0)