Find the value of y and x to the nearest tenth.
|dw:1418908178902:dw|
Well we can use sine to find 'x'. |dw:1418908615633:dw| Sine is \(\sf \dfrac{Opposite}{Hypotenuse}\) \(\sf sin(53^ o) = \dfrac{x}{10}\) Can you solve that? @LilRob
First find \(\sf sin(53^o)\).. \(\sf sin(53^o) = 0.79863551\) Plug that in: \(\sf 0.79863551 = \dfrac{x}{10}\) Multiply 10 to both sides, what's 10 * 0.79863551?
@LilRob
7.98 which rounds to 8. And that is the answer to both values? @iGreen.
No, you gotta multiply 10 * 0.79863551
Tell me what you get.
7.9863551 @iGreen.
Oh, sorry..xD Yes, that's the value of 'x'. Rounded to the nearest tenth would be 8.
You're correct.
Now we have to find 'y'. |dw:1418909045059:dw|
|dw:1418909095097:dw| sorry I think both sides are supposed to be the same length, I just didn't in the picture I drew
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