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How do I solve this type of problem? The square root of 56 over the square root of 50?
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Break down 56 and 50 to prime numbers.
And remember that: \[\sqrt{x \times x} = \sqrt{x} \times \sqrt{x}\]
ok @ankh then what?
Then you can reduce the expression, because you will have things that will repeat in the nominator and in the denominator
Another important rule: \[\sqrt{x} \times \sqrt{x} = x\]
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ok so now I have 28 over 25 in a square root
A radical times a radical cancels out a radical? @ankh
Yup.
28 and 25? Make sure you do a complete prime factorization
I got it! I did the prime thing it's\[\frac{ 2\sqrt{7} }{ 5 }\] Thank you!!!
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