Question

Given F(x)=x-3 and g(x) =1/x^2-9, find [g*f](x)

Answer 1

A. 1/x^2-6x, x=3
B. 1/x^2-6x, x=0,3,6
C. 28-3x^2/x^2-9, x=3
D. 28-3x^2/x^2-9, x=1,3,6

Answer 2

...???

Answer 3

so answer choice C is right

Answer 4

How did you get that?

Answer 5

oh I'm sorry I think it's D

Answer 6

i'm sorry i think i'm doing this wrong

Answer 7

oh ok

Answer 8

ok

Answer 9

so the right answer is C

Answer 10

uhg i keep putting it wrong -.-

Answer 11

\[\frac{ 1 }{ (x-3)^2-9 }\] THERE WE GO, I'm just distracted right now

Answer 12

ok so can you please tell me which one is the right answer from this answer choices a the top

Answer 13

Lets figure it out

Answer 14

\[\frac{ 1 }{ (x-3)^2-3^2 } \implies \frac{ 1 }{ (x-3-3)(-3+x+3) }\] right?

Answer 15

yes

Answer 16

\[\frac{ 1 }{ x(x-3-3) }\] after combining like terms we get this, check me on my math :P
\[\implies \frac{ 1 }{ x(x-6) }\]

Answer 17

So that does equal
\[\frac{ 1 }{ x^2-6x }\]

Answer 18

I was trying to figure if its a or b because I'm not sure you puy x\[x \neq 3 or x \neq 0,3, 6\]

Answer 19

A lot of them don't really make sense huh?

Answer 20

ya that's what I'm confuse with.....

Answer 21

Ok give me one second lol, I'll get back to this.

Answer 22

ok

Answer 23

Ok so my first thought was right, (g*f)(x) is just multiply bleh!

Answer 24

Is the question really asking (g*f)(x) because that is just multiply... @nehapa

Answer 25

it's asking for