Question

x + 3y = 5
-x + 6y = 4
Solve the system of equations.
A)
x = 1, y = 2
B)
x = 2, y = 1
C)
x = 1, y = 1
D)
x = 0, y = 2

Answer 1

I would suggest to add the equations together. This way you can cancel out the Xs, and you will be left with just Ys.

Answer 2

I still don't get it...

Answer 3

Its B

Answer 4

Thank you!!! @thedomination100

Answer 5

Your Welcome . Medal?

Answer 6

@bookworm112
You give a medal by clicking best response next to a person's name.
Though you cannot give out direct answers without an explanation @thedomination100
So, saying this, would you like me to show you exactly how to get to the answer?

Answer 7

@camerondoherty Yes please?

Answer 8

You click best response on my name

Answer 9

Ok, I'll show you c:
You have two equations:
x + 3y = 5
-x + 6y = 4
So first we change up the first equation for x by subtracting 3y from both sides
x = 5 - 3y
Now, we can plug this in for x in the second equation:
-(5 - 3y) + 6y = 4
Can you solve that?

Answer 10

Or do you want me to solve it for you?

Answer 11

I need a medal

Answer 12

Ok, so you have
-(5 - 3y) + 6y = 4
multiply everything in those parenthases by -1
-5 + 3y + 6y = 4
Now you combine like terms:
3y + 6y = 9y
-5 + 9y = 4
You add 5 to both sides
9y = 9
Then you simplify to get
y = 1
Now, using y = 1 you plug it in to either of the equations to find x
In this case, I'm going to use the first equation:
x + 3y = 5
x + 3(1) = 5
x + 3 = 5
Subtract 3 from btoh sides
Then you have:
x = 2
So now we have
x = 2
y = 1
And we make and ordered pair which comes out to
(2, 1) c:

Answer 13

Which, as your options is B
Do you get it @bookworm112 ?

Answer 14

Yes, Thank you!

Answer 15

@camerondoherty

Answer 16

You're Welcome! c: @bookworm112