Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation: CH4 + NH3 + O2  HCN + H2O You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer the following questions: • What is the balanced equation for this reaction? • Which reagent is limiting? Explain why. • How many grams of hydrogen cyanide will be formed?

Question

Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation: CH4 + NH3 + O2  HCN + H2O You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer the following questions: •	What is the balanced equation for this reaction? •	Which reagent is limiting? Explain why. •	How many grams of hydrogen cyanide will be formed?

cuanchi · Answer

2CH4 + 2NH3 +3O2 -> 2HCN + 6H2O

8g/16g= 0.50 moles of HCN  limiting reactanct CH4
10g/17g=058 moles of HCN

0.5 x 27=13.5g HCN