Question

A sold an article to B at a profit of 30%. B sold it to C for $2912 at a loss of 20%. THe original cost of the article is?

Answer 1

@mathmath333

Answer 2

then?

Answer 3

oh

Answer 4

is it $2800 thanks

Answer 5

this will make it clear
\(\large\tt \begin{align} \color{black}{x\implies x+30\%x\\=x+\dfrac{30x}{100}\\~\\
let y=x+\dfrac{30x}{100}\\~\\
=\dfrac{130}{100}x\\~\\
y\implies y-\%20y \\
=y-\dfrac{20}{100}y\\
=\dfrac{80}{100}y\\
=\dfrac{80}{100}\dfrac{130}{100}x\\~\\~\\~\\
\dfrac{80}{100}\dfrac{130}{100}x=2192
}\end{align}\)

Answer 6

* correction last line\(\large\tt \begin{align} \color{black}{
\dfrac{80}{100}\dfrac{130}{100}x=2912
}\end{align}\)

Answer 7

one approach
let the original price of the article = P
then 2 equations B paid 30% more = 1.3P
and C paid 2912 at 20%loss so 80% of (1.3P)
0.80*(1.3P) = 2912
to solve for P
2912/ (0.80*1.3) = 2800