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Use the definition of limit (epsilon-delta) or (sequentially limit) that if \(\lim_{x\to c}f(x)=L\neq 0\) then \(\lim_{x\to c}\frac{1}{f(x)}=\frac{1}{L}\)
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lol go look at the example I just posted in the other question, weird...
This falls out directly from the sequential version, but you need the bounded away from 0 property to prove that. Do you know this property?
if a sequence converges to a non zero number a, then there is an M such that for all n>m we have that |f(x)|> |a|/2
well, it needs proof as well :)
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